Bantu jawab ya No 10

PecahaN BersusuN

[tex] \frac{ \frac{a+2}{4} }{ \frac{a^2 - 4}{8} } X \frac{8}{8}\,= [/tex]

[tex]=\, \frac{2(a+2)}{a^2 - 4 } \, = \frac{2(a+2)}{(a+2)(a-2)}\,= \frac{2}{a- 2} [/tex]