tlong bntuannya ya kak...

1) dik : CD = 15 cm
        AB = 25 cm
    dit : luas trapesium ?
    jawab
    luas trapesium = t ×[tex] \frac{CD + AB}{2} [/tex]
                            = 12 ×[tex] \frac{15+25}{2} [/tex]
                            =12 × [tex] \frac{40}{2} [/tex]
                            = 12 x20
                            = 240 [tex] cm ^{2}[/tex]
                           
2) dik : AB = 12 cm
            CD =24 cm
             AD =6 cm
     dit : luas trapesium?
     jawab :
     luas trapesium = [tex]6 x \frac{12+24}{2} [/tex]
                             = 6 × [tex] \frac{36}{2} [/tex]
                             = 6 × 18
                             = 108 [tex] cm^{2} [/tex]