Matematika

Pertanyaan

jika f(x)=x2+3x-2 dan g(x)=2x+3, nilai ( f o g ) (-2)=

1 Jawaban

  • fog(x) (2x+3)^2+3(2x+3)-2 = 4x^2+12x+9+6x+9-2 = 4x^2+18x+16
    fog(-2)= 4(-2)(-2)+18(-2)+16
    = 16-36+16 = -4

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