Suatu persegi panjang mempunyai panjang (8x+6)cm Dan lebar (10x-7).bila keliling 102 cm berapa panjang Dan lebarnya

Bangun Datar
• persegi panjang

p = 8x + 6 cm
l = 10x - 7 cm

Keliling = 102 cm
2(p + l) = 102
p + l = 102/2
8x + 6 + 10x - 7 = 51
18x - 1 = 51
18x = 52
x = 52/18
x = 26/9

p = 8x + 6
p = 8 . 26/9 + 6
p = 208/9 + 54/9
p = 262/9
p = 29 1/9 cm ✔

l = 10x - 7
l = 10 . 26/9 - 7
l = 260/9 - 63/9
l = 197/9
l = 21 8/9 cm ✔

p= 8x+6
= 8.26/9+6
= 208/9+54/9
= 262/9
p= 29 1/9 cm

l= 10x-7
= 10. 26/9-7
= 260/9-63/9
= 197/9
= 21 8/9 cm

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