fungsi f:x=px²+qx dengan p dan q bilangan bulat.jika f(2)=-2 dan f(-2)=10,nilai p dan q adalah.... tolong di jawab...

Materi : Fungsi 



f(x) = px² + qx
f(2) =  4p + 2q = -2
f(-2) = 4p - 2q = 10
         ------------------- (+)
                 8p = 8
                   p = 1
subtitusi nilai p = 1 ke
4p + 2q = -2
4 + 2q = -2
2q = -6
q = -3

jadi nilai
p = 1
q = -3

F(x) =px²+qx
F(2) => 4p+2q=-2
F(-2) => 4p -2q =10 (-)
=> 4q=-12
=> q = -3

4p+2q = -2
4p + 2(-3) =-2
4p -6 =-2
4p=4
p=1