nilai dari lim (√4x²-8x+6 - √4x² + 16x-3)

[tex]lim_{x - \infty } ( \sqrt{4x^{2} -8x+6} - \sqrt{4x^{2} + 16x-3)} \\ = \frac{ - 8 - 16}{2 \sqrt{4} } \\ = \frac{ - 24}{4} \\ = - 6[/tex]