fungsi f di nyatakan dengan rumus f(x) = ax + b .jika f(2) =11 dan f(-5) =-10,nilai dari (a+b)² adalah

f(x) = ax + b

f(2) = 11
2a + b = 11

f(-5) = -10
-5a + b = -10

2a + b = 11
-5a + b = -10
------------------ -
7a = 21
a = 3

2a + b = 11
2(3) + b = 11
6 + b = 11
b = 11 - 6
b = 5

(a + b)² = (3 + 5)² = 8² = 64

f(x) = ax + b
f(2) =11 
a(2)+b=11
2a+b=11

 f(-5) =-10
a(-5)+b=-10
-5a+b=-10

dieliminasi
2a+b=11
-5a+b=-10
________-
7a=21
a=21/7=3

2a+b=11
2(3)+b=11
6+b=11
b=11-6
b=5

(a+b)²=(3+5)²=8²=64