Matematika

Pertanyaan

tentukan 2log12+2log6-2log5=

1 Jawaban

  • sifat logaritma

    alogb + alogc = alog(b.c)

    alogb - alogc = alog(b/c)

    alogb = logb/loga

    =2log12 +2log6 - 2log5

    =2log12 + 2log(6/5)

    = 2log12 + 2log1,2

    = 2log(12.1,2)

    =2log14,4

    = log14,4 / log2

    = 1,15 / 0,3

    = 3,83


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