4L +48 cm3= 5Ml + 1.400 L = 5 Dl3 + 12m3= 8Hl + 2 Kl3 = 4cn3 + 6L = 10cc3 + 25 Ml3 = 9Km3 + 2dam3 = m3 11m3 + 7L = cc 6kl + 12dal = cc 4ml + 5cl =
Matematika
adhit61
Pertanyaan
4L +48 cm3=
5Ml + 1.400 L =
5 Dl3 + 12m3=
8Hl + 2 Kl3 =
4cn3 + 6L =
10cc3 + 25 Ml3 =
9Km3 + 2dam3 = m3
11m3 + 7L = cc
6kl + 12dal = cc
4ml + 5cl = cm3
8L + 12dc= cm3
17m3 + 12 dc =
5Ml + 1.400 L =
5 Dl3 + 12m3=
8Hl + 2 Kl3 =
4cn3 + 6L =
10cc3 + 25 Ml3 =
9Km3 + 2dam3 = m3
11m3 + 7L = cc
6kl + 12dal = cc
4ml + 5cl = cm3
8L + 12dc= cm3
17m3 + 12 dc =
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