jika f(3x-5)=7x+2,maka f-1(x)=

f(3x-5)=7x+2
= 7 (3x - 5) + 2
= 21x - 35 + 2
= 21x - 33

f^-1 (x) = 21x - 33
y = 21x - 33
y + 33 = 21x
x = (y + 33) / 21

f^-1 (y) = (y + 33) / 21
f^-1 (x) = (x+ 33) / 21