Matematika

Pertanyaan

2x-y+4=0 dan -6x+y-2=0 bentuk eliminasi

1 Jawaban

  •  -6x+y-2=0 
    y = 6x + 2

    2x-y+4=0 
    2x - (6x + 2) + 4 = 0
    2x - 6x - 2 + 4 = 0
    -4x = -4 + 2
    -4x = -2
    x = 1/2

    2x-y+4=0
    2x = y - 4
    x = 1/2y - 2

    -6x+y-2=0
    -6(
    1/2y - 2) + y = 2
    -3y + 12 = 2
    -3y = 2 - 12
    -3y = -10
    y = 10/3

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