jika cos A 3/5 kuadran 2, cos b -5/13 b kuadran 3 tentukan nila sin (A+B)

Materi : Trigonometri


cosA = -3/5
A berada di kuadran 2
maka 
sin A = 4/5

cosB = -5/13
B berada di kuadran 3
maka
sinB = -12/13

sin(A+B)
= sinA . cosB + cosA . sinB
= (4/5)(-5/13) + (-3/5)(-12/13)
= -20/65 + 36/65
= 16/65

sin(a+b)
= sin a. cos b + cos a. sin b
= (4/5)(-5/13)+(-3/5)(-12/13)
= -20/65+36/65
= 16/65

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