Tolong dibantu ya ^_^ a (t) = 2t² + 2t +1² Tentukan jarak (s/t) dengan rumus v akhir = v awal + integral × a × d × t dan s akhir = s awal + integral × v × d × t

v = integral a dt
v = integral 2t^2 + 2t + 1
v = 2/3t^3+t^2+t+a

s = integral v dt
s = 1/6t^4+1/3t^3+1/2t^2+at+b

[tex]v=v0+ integral ( 2t^{2}+2t+1)dt \\ v=0+ \frac{2}{3}t^{3} + t^{2} +t \\ \\ \\ s=s0+ integral (\frac{2}{3}t^{3} + t^{2}+t)dt=0+ \frac{2}{12}t^{4} +\frac{1}{3} t^{3} +\frac{1}{2} t \\ s=\frac{1}{6}t^{4}+\frac{1}{3} t^{3}+\frac{1}{2} t[/tex]