melalui titik(1,1) dan sejajar garis 2x+3y=-3

Persamaan Garis
SMP Kelas VIII

ax + by + c = 0

m = -a/b

2x + 3y = -3
m = -2/3

Sejajar, maka m1 = m2 = -2/3

Melalui titik (1, 1)
(y - y1) = m(x - x1)
(y - 1) = -2/3(x - 1)
3(y - 1) = -2(x - 1)
3y - 3 = -2x + 2
3y = -2x + 2 + 3
3y = -2x + 5
2x + 3y = 5