Xlog(x+6) + xlog(x—1) = 2+xlog 2
Matematika
kai30
Pertanyaan
Xlog(x+6) + xlog(x—1) = 2+xlog 2
1 Jawaban
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1. Jawaban Anonyme
jawab
ˣlog (x+6)+ ˣlog (x-1) = ˣlog x² + ˣlog 2
ˣlog(x+6)(x-1) = ˣlog(x²)(2)
(1)
(x+6)(x-1) = 2x²
x² + 5x - 6 = 2x²
x² - 5x + 6 = 0
(x - 3)(x - 2)= 0
x = 3 atau x = 2
(2)
syarat logaritma
x+6 > 0 n x-1> 0 n x > 0
x > -6 n x> 1 n x > 0
x > 1
hp x = (2 ,3 )