sederhanakanlah!!! 1.40x²yz : 15xy 2.28ab²c : 3abc

1.
[tex]40 x^{2} yz \div 15xy \\ = (40 \div 15)(x ^{ 2 - 1} )(y ^{1 - 1} )(z) \\ = 2 \frac{2}{3} xz[/tex]

2.
[tex]28ab ^{2} c \div 3abc \\ = (28 \div 3)(a ^{1 - 1} )(b ^{2 - 1} )(c ^{1 - 1} ) \\ = 9 \frac{1}{3} b[/tex]

Maaf Kalau Salah