diketahui fungsi f(x)=2x-2, g(x)=x²-1. ditanya :(fog)(x+1)

jawab

f(x)= 2x - 2
g(x)= x²  - 1

(fog)(x+1)= f{g(x+1)}
(fog)(x+1)= f{(x+1)²- 1}= 2 {(x+1)² - 1} - 2
= 2 (x²+2x+ 1 - 1) - 2
= 2(x² + 2x) - 2
= 2x²+ 4x - 2