bantuin dong, kalo masalah matematika aku kurang paham

Materi Peluang

2.]
a. P(A) = n(A) / n(S)
= ⅙

b. P(B) = 1 - P(A)
= 1 - ⅙ = ⅚

3.]
P(H) = 0,8
P(TH) = 1 - P(H)
= 1 - 0,8 = 0,2

______________________________

2.]
N = 300

a. P(A) = n(A) / n(S)
= ⅙
Maka

E(A) = P(A) • N
= ⅙ • 300 = 50 kali

b. P(B) = n(B) / n(S) ... [kelipatan tiga: 3 , 6]
= 2/6 = ⅓

E(B) = P(B) • N
= ⅓ • 300 = 100 kali

c. P(C) = n(C) / n(S) ... [prima : 2 , 3 , 5]
= 3/6 = ½

E(C) = P(C) • N
= ½ • 300 = 150 kali

manalah saya tahu maaf ya